Add File

history/005_letter_test/src/main/java/com/github/drinkjava2/frog/brain/Hole.java

@@ -0,0 +1,58 @@
+/*
+ * Copyright 2018 the original author or authors. 
+ * Licensed under the Apache License, Version 2.0 (the "License"); you may not
+ * use this file except in compliance with the License. You may obtain a copy of
+ * the License at http://www.apache.org/licenses/LICENSE-2.0 Unless required by
+ * applicable law or agreed to in writing, software distributed under the
+ * License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS
+ * OF ANY KIND, either express or implied. See the License for the specific
+ * language governing permissions and limitations under the License.
+ */
+package com.github.drinkjava2.frog.brain;
+
+/**
+ * Hole is a hole on jelly cell, it works like synapse on nerve cell
+ * 
+ * 以前叫突触，现在改名叫洞，更形象一点，每个光子传来就好象在果冻上砸出个洞。管它符不符合生物脑突触这个形象，张牙舞爪的神经元变成了千创百孔的果冻，先乱试一通再说。
+ * 
+ * @author Yong Zhu
+ * @since 2.0.2
+ */
+public class Hole {
+	public float x;// x,y,z 是 洞的中心坐标点，这个是脑内的绝对坐标
+	public float y;
+	public float z;
+	public float mx; // mx,my,mz分别是光子砸出这个洞时的光子每单元移动方向在三个轴上的投影
+	public float my;
+	public float mz;
+	public int size = 50;// 洞的大小1~100，这个size会按记忆曲线慢慢回复到0，接近0后这个洞就被删除回收内存，
+	public int age;// 洞的年龄,一直在增长，但一个洞有完全同向的光子再次砸进来，洞的年龄就归0
+	public int organNo;// 这里记录第一个撞出来这个洞的产子是由哪个器官产生出来的
+
+	public Hole(Photon p) {
+		this.x = p.x;
+		this.y = p.y;
+		this.z = p.z;
+		this.mx = p.mx;
+		this.my = p.my;
+		this.mz = p.mz;
+		this.organNo = p.organNo;
+	}
+
+	public float angleCompare(Hole p) {// 比较洞与光子之间的角度差值
+		return Math.abs(p.mx - mx) + Math.abs(p.my - my) + Math.abs(p.mz - mz);
+	}
+
+	public float angleCompare(Photon p) {// 比较洞与光子之间的角度差值
+		return Math.abs(p.mx - mx) + Math.abs(p.my - my) + Math.abs(p.mz - mz);
+	}
+
+	public boolean ifSameWay(Photon p) {// 如果光子运动方向与洞完全同向,实际上也就是说从同一个波源发出来的
+		return Math.abs(p.mx - mx) < 0.0001 && Math.abs(p.my - my) < 0.0001 && Math.abs(p.mz - mz) < 0.0001;
+	}
+
+	public boolean ifSimilarWay(Photon p) {// 如果光子运动方向与洞近似相同
+		return Math.abs(p.mx - mx) < 0.05 && Math.abs(p.my - my) < 0.05 && Math.abs(p.mz - mz) < 0.05;
+	}
+
+}